***EDIT***Sorry for a second there, I tried to convince myself that F(adsbygoogle = window.adsbygoogle || []).push({}); _{N}was not equal to_{Fg}, but it must.

Given the coefficient of static friction (.4) between an egg and a pan, what is the smallest angle from the horizontal taht will cause the egg to slide?

Here's my drawing:

(http://i51.photobucket.com/albums/f362/BeamsBox/PhysicsEgg.jpg)

Here's my work:

x, implying that it's along the x-axis

F_{s}is static friction force

F_{g}is the force of gravity

m = mass

a = acceleration

(mue) = .4, the coefficient of friction

F_{s(max)}= (mue)F_{N}Equation 1

F_{N}= mg

Substitute to get:

F_{s(max)}= (mue)(mg) Equation 2

F_{(net)x}= ma_{x}

F_{s}- F_{gx}= ma_{x}

Since it is stationary, a = 0

F_{s}- F_{gx}= m(0)

F_{s}= F_{gx}Equation 3

Now substitute (mue)(mg) for F_{s},

(mue)(mg) = F_{gx}, and substitute the F_{gx}from the diagram,

(mue)(mg) = F_{g}sin(theta), and substitute mg for F_{g}

(mue)(mg) = (mg)sin(theta), mg cancels out

(mue) = sin(theta), and substitute the known .4 for (mue),

.4 = sin(theta)

theta = sin^{-1}(.4)

theta = about 23.6 degrees

The book says 2... any ideas on where I may have gone wrong?

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# Homework Help: Sliding egg I think the books wrong, could someone please verify?

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