- #1
BoogieL80
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I've gotten stuck on the following problem:
The drawing shows a rectangular block of glass (n = 1.52) surrounded by liquid carbon disulfide (n = 1.63). A ray of light is incident on the glass at point A with a = 34.0° angle of incidence. At what angle of refraction does the ray leave the glass at point B?
http://www.boomspeed.com/boogiel80/refraction.gif [Broken]
I was using the formula n1sin theta1 = n2 sin theta2 and manipulated the foruma for sin theta2 (I assumed the liquied was n1 and the glass was n2). I then found the inverse sin of my answer to get the angle. I got an answer of 36.8 degrees. Webassign told me that was incorrect. I thought that maybe since the angle was going back into the same liquid that maybe it would be the same as the angle of incidence, but that was also incorrect. Any feedbook would be appreciated.
The drawing shows a rectangular block of glass (n = 1.52) surrounded by liquid carbon disulfide (n = 1.63). A ray of light is incident on the glass at point A with a = 34.0° angle of incidence. At what angle of refraction does the ray leave the glass at point B?
http://www.boomspeed.com/boogiel80/refraction.gif [Broken]
I was using the formula n1sin theta1 = n2 sin theta2 and manipulated the foruma for sin theta2 (I assumed the liquied was n1 and the glass was n2). I then found the inverse sin of my answer to get the angle. I got an answer of 36.8 degrees. Webassign told me that was incorrect. I thought that maybe since the angle was going back into the same liquid that maybe it would be the same as the angle of incidence, but that was also incorrect. Any feedbook would be appreciated.
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