Snell's Law/Critical Angles Problem

  • Thread starter Thread starter Nikki196
  • Start date Start date
  • Tags Tags
    Angles
AI Thread Summary
To solve critical angle problems involving Snell's Law with a circular geometry, it's essential to understand the relationship between the incident angle and the tangent line at the point of incidence. Providing a clear diagram of the problem can facilitate better assistance. The incident angle is measured relative to this tangent line rather than the radius of the circle. Utilizing these geometric principles will help in accurately determining the incident angle. Understanding these concepts is crucial for effectively applying Snell's Law in this context.
Nikki196
Messages
3
Reaction score
0
I know how to do critical angle problems, using snell's law, but i was given a circle and I'm not sure how i should go about finding the incident angle.. If someone could help me out with that it would be awesome! THX
Nicole
 
Physics news on Phys.org
Nikki196 said:
I know how to do critical angle problems, using snell's law, but i was given a circle and I'm not sure how i should go about finding the incident angle.. If someone could help me out with that it would be awesome! THX
Nicole


Post the exact text of the problem and maybe attach some drawing,since this is a problem that will use some geometry.And it's Snell-Descartes law.
That is if u want us to help u...

Daniel.
 
If your light ray is reflecting off a circle (or cylinder), the angle is the angle made with the tangent line to the circle.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top