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**Snell's Law HELP!! TEST TOMMOROW!!!**

## Homework Statement

Hi, I have a problem with Snell's Law...i understand that it is:

n1(sin)theta1 = n2(sin)theta2

but for the test, we need to know how to manipulate the problem to find the angle of refraction...i will have a calculator to plug thing in but i just don't understand how to!!! Apparently after you find one thing you need to use an inverse sin (sin-1) or something...PLEASE HELP!!!

An example problem for this is:

A Beam of light passes from glass (n=1.51) to an unknown medium X (nX=?).

If the angle of incidence is 40 and the angle of refraction is 29 then the index of refraction of the unknown medium is closest to:

a)1.17, b)1.38, c)1.63, d)1.83 or e)2.00

Followed by: The beam of light exists medium X and enters air. If it has an incident angle of 29 at the X-Air boundary, find the angle of refranction in the air?

## The Attempt at a Solution

for example my notes say: Nw(sin)theta W = Na(sin)theata A

w=water=1.333

a=air=1

1.333(sin)theta W=1 x sin(37)(angle of incidence)

sin thetaW=sin(37)/1.333

Theta W= (sin -1)/(inverse sin) [sin(37)/1.333]

WHY IS IT GO FROM SIN(theta W) TO INVERSE SIN!?

I Know there is a lot fo questions and info here...these are questoins from a quiz i did and i did very poorly...my test is tommorow and help would be greatly appretiated THANKS SOOO MUCH!!