Calculating Refraction: Snells Law Help for Light Ray Approaching Glass Block

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Homework Help Overview

The discussion revolves around applying Snell's law to determine the angle of refraction for a light ray approaching a glass block at an angle of 30° to the normal. The refractive indices of air and glass are provided as 1 and 1.5, respectively.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Snell's law and the algebraic manipulation involved in solving for the angle of refraction. There are questions about the correctness of calculations and the handling of negative values in the results.

Discussion Status

Several participants have pointed out potential errors in algebraic steps and the importance of ensuring the calculator is set to the correct mode (degrees vs. radians). There is an ongoing exploration of the calculations without a clear consensus on the correct approach yet.

Contextual Notes

Participants are addressing issues related to calculator settings and algebraic manipulation, indicating a focus on understanding the mathematical process rather than arriving at a final answer.

Sprattboy
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Snells law -- help please

A light ray approaches a glass block at 30° to the normal. The refractive
indices of air and water are 1 and 1.5 respectively At what angle will the light
be refracted? This uses Snells law

I did Sin 30 / Sin r = 1 / 1.5
I then multiplied both sides in order to get rid of sin 30.
After that, I got Sin r = 1/1.5(xSin30)
This gave me an answer of -1.48
When I do inverse sine it gives me an error
What did I do wrong?
 
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Sprattboy said:
A light ray approaches a glass block at 30° to the normal. The refractive
indices of air and [STRIKE]water[/STRIKE] glass (?) are 1 and 1.5 respectively At what angle will the light
be refracted?


This uses Snells law

I did Sin 30 / Sin r = 1 / 1.5
I then multiplied both sides in order to get rid of sin 30.
After that, I got Sin r = 1/1.5(xSin30)
This gave me an answer of -1.48
When I do inverse sine it gives me an error
What did I do wrong?
Check your algebra !
 
SammyS said:
Check your algebra !

I have
 
Check it again and again, just to be sure, a minus answer should be rather unlikely in elementary examples.
 
Sprattboy said:
I did Sin 30 / Sin r = 1 / 1.5
I then multiplied both sides in order to get rid of sin 30.
After that, I got Sin r = 1/1.5(xSin30)
You did your fractions wrongly.

You should have got this:

\frac{1}{sin(r)}=\frac{1}{1.5(sin(30))}
 
Make sure your calculator is set for degrees instead of radians. You're getting a negative sign because you're using radians. That's what happens when you blindly follow the calculator without a clue of what to expect. You end up eating calculator garbage.
 
What dauto said. and:

Since you have done that,(Did it using radians), be sure to reset your calculator especially before exams.
 

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