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negation

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Mod note: Corrected a typo in the problem statement.

[STRIKE]If[/STRIKE]Is the vector AP parallel to u?

u= (1,4,-3)

A(-2,-1,-2)

I do know that if AP is parallel to u then there must be some scalar multiple such that Ax = u.

I think it's a matter of setting up the question that I'm muddled.

Anyway, my attempt.

Let A = a

(a

-2a

-a

-2a

in augmented form:

-2,0,0|-1

0,2,0|-4

0,0,2|3

REF...

a

a

a

## Homework Statement

[STRIKE]If[/STRIKE]Is the vector AP parallel to u?

u= (1,4,-3)

A(-2,-1,-2)

## The Attempt at a Solution

I do know that if AP is parallel to u then there must be some scalar multiple such that Ax = u.

I think it's a matter of setting up the question that I'm muddled.

Anyway, my attempt.

Let A = a

_{1},a_{2},a_{3}(a

_{1},a_{2},a_{3})(-2,-1,-2) = (1,4,3)-2a

_{1}= 1-a

_{2}=4-2a

_{3}= 3in augmented form:

-2,0,0|-1

0,2,0|-4

0,0,2|3

REF...

a

_{1}= -1/2a

_{2}= -2a

_{3}= 3/2
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