Vector S, dimension of subspace Span(S)?

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Homework Help Overview

The discussion revolves around determining the dimension of the subspace spanned by a set of vectors S = {a1, a2, a3, a4} in R5. Participants are also exploring which vectors from S can form a basis for Span(S).

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the dimension of Span(S) and whether it can be equal to the number of vectors in S. There is confusion regarding the definitions of span and basis, with some questioning the relationship between them.
  • One participant attempts to use row elimination on a matrix formed by the vectors to determine the dimension, concluding it to be 3.
  • Questions are raised about how to identify which vectors form a basis for Span(S) and the meaning of certain variables (k1, k2, etc.) in the context of the problem.

Discussion Status

The discussion is active, with participants clarifying concepts and exploring the implications of their findings. Some guidance has been offered regarding the elimination of certain vector sets based on the determined dimension. However, there is no explicit consensus on the basis vectors yet.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can use or the methods they can apply. There is an ongoing exploration of foundational definitions related to vector spaces.

concon
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Homework Statement



Consider the set of vectors S= {a1,a2,a3,a4}
where
a1= (6,4,1,-1,2)
a2 = (1,0,2,3,-4)
a3= (1,4,-9,-16,22)
a4= (7,1,0,-1,3)

Find the dimension of the subspace Span(S)?

Find a set of vectors in S that forms basis of Span(S)?

Homework Equations


dimension of V = n in Rn?

The Attempt at a Solution



- Part one: Dimension

If equation is true and Span(S) is in fact basis of V then is the dimension 4? Is it that easy?

- Part two: Basis
Is this asking for the k1,k2,k3,k4 that make Span(S) = V?
 
Last edited:
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concon said:

Homework Statement



Consider the set of vectors S= {a1,a2,a3,a4}
where
a1= (6,4,1,-1,2)
a2 = (1,0,2,3,-4)
a3= (1,4,-9,-16,22)
a4= (7,1,0,-1,3)

Find the dimension of the subspace Span(S)?

Find a set of vectors in S that forms basis of Span(S)?

Homework Equations


dimension of V = n in Rn?




The Attempt at a Solution



- Part one: Dimension

If equation is true and Span(S) is in fact basis of V then is the dimension 4? Is it that easy?
What equation?

Span(S) is a subspace, not a basis. To say that Span(S) is a basis of V doesn't make any sense.

- Part two: Basis
Is this asking for the k1,k2,k3,k4 that make Span(S) = V?
What are the k's supposed to be?

It seems you're not clear about basic definitions of terms like span and basis. You should get those down first before you attempt to do this problem.
 
vela said:
What equation?

Span(S) is a subspace, not a basis. To say that Span(S) is a basis of V doesn't make any sense.


What are the k's supposed to be?

It seems you're not clear about basic definitions of terms like span and basis. You should get those down first before you attempt to do this problem.
Sorry my reply was confusing I mixed up a few terms here and there.
So what I have determined thus far:
1. the dimension is 3
I used row eliminations in a matrix with [ a1 a2 a3 a4] and got two rows of zeroes out of the total five rows. Thus 5-2 = 3 and the dimension is 3.

2. what I need to figure out now is which of the vectors is a basis for the Span(S). How do I do this?

the options are:
{a2,a3}
{a1,a2,a3}
{a1,a2}
{a1,a2,a3,a4}
{a1,a2,a4}
 
Since you have already determined that the dimension is three, those sets of two or four vectors are immediately eliminated. To determine whether {a1, a2, a3} or {a1, a2, a4} is a basis, do the same thing you did with the entire set. See if they are linearly independent.
 

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