Solar Cell calculating the power output

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SUMMARY

The discussion centers on calculating the power output of a solar cell by measuring the electrical energy converted from light energy. The initial approach suggested using a voltmeter and ammeter directly across the solar cell, which is ineffective due to the lack of energy dissipation in the circuit. A more viable method involves using a capacitor to store energy temporarily and then discharging it through a resistor, applying the formula E=0.5CV² to calculate energy. However, the variability in voltage and current during the capacitor charging process complicates this method.

PREREQUISITES
  • Understanding of basic circuit theory
  • Familiarity with solar cell operation and characteristics
  • Knowledge of capacitor charging and discharging principles
  • Proficiency in using formulas such as P=IV and E=0.5CV²
NEXT STEPS
  • Research the characteristics of solar cells and their I-V curves
  • Learn about variable resistors and their application in load testing
  • Study capacitor behavior in charging and discharging circuits
  • Explore advanced methods for measuring power output in renewable energy systems
USEFUL FOR

This discussion is beneficial for physics students, renewable energy enthusiasts, and anyone involved in experimental design related to solar energy systems.

hickyai5
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Homework Statement


I am asked to plan a practical to determine the power output of a solar cell, i.e how much light energy is converted toe electrical energy per second. Now I thought(obviously) to just connect voltmeter across it with an ammeter and use PVI, however thinking about it, I don't know if this would work. It might just be my circuit theory but there is nowhere for the energy to go out of the circuit and so won't it just build up so that you have all the electrical energy it has produced as well as what it is producing now. I had another method for it, however, from the mark allocation I think it is too complicated especially as at first this seems like a really easy solution. My more complicated method, was to store all the energy for say a one sec burst of light, on a capacitor and then to discharge it through a resistor with a voltmeter across it, then using V= Vo*e^(-t/RC) to calculate initial voltage across the capacitor and ten use E= o.5CV^2 Can someone just explain why the first method is wrong/right cos its proper fuzzled my way fo thinking of things, btw I'm jst finishing a-level physics to go do it at uni, so i understand most things, but this jst got me thinking


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The Attempt at a Solution

 
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use a variable resistance/and measure the current and voltage for a range of load resistances at a constant light intensity. If you short the cell you get maximum current and no power, and if you have an open circuit you get maximum voltage and also no power. The maximum power delivered to the load should be somewhere between that.

Your capacitor idea is problematic because the voltage and current won't be constant when charging it.
 
thanks, very much,
 

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