Solid sphere rolling along a track

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SUMMARY

The discussion centers on the mechanics of a solid sphere rolling along a track and the conservation of energy principles involved. The initial and final energy states are represented by the equation Ei = Ef. A participant initially believes that the sphere will maintain its height after leaving the track due to inertia, but is corrected to understand that the sphere will continue to rotate, resulting in a lower height than initially expected due to reduced kinetic energy (KE) after leaving the track.

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  • Understanding of conservation of energy principles in physics
  • Knowledge of rotational motion and kinetic energy concepts
  • Familiarity with gravitational potential energy calculations
  • Basic mechanics of solid spheres and their motion
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  • Study the principles of conservation of mechanical energy in rolling motion
  • Learn about the relationship between rotational and translational kinetic energy
  • Explore the effects of inertia on the motion of rolling objects
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JessicaHelena
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Homework Statement


Please see the attached file.

Homework Equations


Ei = Ef

The Attempt at a Solution


I don't have an answer key provided, but I'd really like to verify that I'm right (or if I'm wrong, why). I think ti'd be (c) because assuming that due to inertia, B will continue going straight up (even though gravity will decelerate its motion). When it finally stops moving, it will have 0 KE, but assuming the energy is conserved, it should have the same amount of mechanical energy as it did in A. Since at A, the ball had only gravitational potential energy (mgh), at its highest point in air, it too should have mgh and thus the same height as point A.

Would that be right?
 

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No, it would not be right. Will the ball be rotating after it leaves the track?
 
@Chestermiller — ah, it'd keep rotating even when it's stopped moving vertically, and so with less KE available "initially", the mgh will be less as well and thus the height will be less than the original height. Is that better?
 
JessicaHelena said:
@Chestermiller — ah, it'd keep rotating even when it's stopped moving vertically, and so with less KE available "initially", the mgh will be less as well and thus the height will be less than the original height. Is that better?
If I understand you correctly, yes.
 
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