- #1
Big-Daddy
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Normally due to H+ being the reference state in solution, all 'standard molar' state variables and 'standard value of formation' state variables are 0 for it. But H2(g) has a standard enthalpy of formation = 0 and standard molar entropy of 115 Jmol-1K-1. Then shouldn't ΔG°(298) for the reaction
2H+(aq) + 2e- = H2(g)
be -34,720 J and K = 1 * 106, E°=+0.1799?
But I thought according to electrochemistry that E°=ΔG°=0 for this reaction and thus K=1.
2H+(aq) + 2e- = H2(g)
be -34,720 J and K = 1 * 106, E°=+0.1799?
But I thought according to electrochemistry that E°=ΔG°=0 for this reaction and thus K=1.
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