MHB Solution for Optimal Number of Issuance Counters and Loading Bays

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The discussion centers on determining the optimal number of equipment issuance counters and loading bays in a workplace scenario involving 30 individuals. With one issuance counter and five loading bays, the workflow requires each person to first receive equipment and then load it, with specific time parameters for each task. The individual seeks a formula to calculate total processing time based on varying parameters, including the time taken to issue and load equipment. The challenge is compounded by the limitation of the issuance counter, which can serve only one person at a time. The conversation aims to simplify the problem into manageable parts to facilitate the creation of a solution.
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Hi there everyone, need help with a work assignment which I feel is simple but I just cannot wrap my mind around it. Not too sure if this is the correct thread though, so I beg for your forgiveness if it is the wrong thread. :X

Premise:
At a certain workplace, there are 5 equipment loading bays, and 1 equipment issuance counter.

The work flow is as such:

1) Person goes to the issuance counter to draw his equipment.
2) Person goes to the equipment loading bay to load his equipment.
3) Person leaves the area.

Parameters:

A) Total number of persons
B) Time it takes for person to draw his equipment
C) Time it takes for person to load his equipment

Assumption:

The issuance counter can only handle one person at a time.

Question:

So say if I have 30 persons, and it takes 2 minutes for the person to equip his items, and 1 minute for the equipment to be issued at the counter, how long is it going to take with just 5 equipment loading bays and 1 equipment issuance counter?

I have been racking my brains as to come up with a formula for Excel so that I can vary the above-mentioned parameters and come up with an optimal ratio of equipment loading bays to equipment issuance counters…

My math is rather rusty and this is work assignment given by my boss. I have not practiced math for about 4 years since graduation and my boss is rather demanding… Sigh. Help... please?

Much thanks to anyone who can help in advance. :)
 
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sleepingneko said:
Hi there everyone, need help with a work assignment which I feel is simple but I just cannot wrap my mind around it. Not too sure if this is the correct thread though, so I beg for your forgiveness if it is the wrong thread. :X

Premise:
At a certain workplace, there are 5 equipment loading bays, and 1 equipment issuance counter.

The work flow is as such:

1) Person goes to the issuance counter to draw his equipment.
2) Person goes to the equipment loading bay to load his equipment.
3) Person leaves the area.

Parameters:

A) Total number of persons
B) Time it takes for person to draw his equipment
C) Time it takes for person to load his equipment

Assumption:

The issuance counter can only handle one person at a time.

Question:

So say if I have 30 persons, and it takes 2 minutes for the person to equip his items, and 1 minute for the equipment to be issued at the counter, how long is it going to take with just 5 equipment loading bays and 1 equipment issuance counter?

I have been racking my brains as to come up with a formula for Excel so that I can vary the above-mentioned parameters and come up with an optimal ratio of equipment loading bays to equipment issuance counters…

My math is rather rusty and this is work assignment given by my boss. I have not practiced math for about 4 years since graduation and my boss is rather demanding… Sigh. Help... please?

Much thanks to anyone who can help in advance. :)

Hi sleepingneko! Welcome to MHB! (Smile)

Let's see if we can break this down into smaller and simpler pieces.

Suppose there was only 1 person.
At which time will he have his equipment and at which time will he be done equipping his items?

Now suppose there is a 2nd person.
When can he start getting his equipment?
Where can he load his equipment when he has it?
And when will he be ready?
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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