Solve 3D Vector V1-V2+V3 Equations: Find V1,V2,V3 & Magnitude & Direction of V

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The discussion focuses on solving a system of three equations involving three-dimensional vectors V1, V2, and V3. The equations are V1–V2 + V3 = 2i + 2j + 3k, V1–2V2-2V3 = -5i + 7j + 8k, and V1 + V2 + V3 = 4i - 2j - k. Participants suggest using substitution and elimination methods to solve for the vectors, treating the problem like simultaneous equations. A proposed method involves manipulating the equations to eliminate one variable, making it easier to solve for the others. The goal is to find V1, V2, V3, and subsequently determine the vector V and its magnitude and direction.
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V1–V2 +V3 = 2i+2j+3k, V1– 2V2-2V3 = -5i+7j+8k, and V1+V2+V3 = 4i-2j-k

a) Find V1,V2, and V3

b) Find V=V1+V3 in terms of its components. What is the magnitude and direction of V?


All I know is that they are three dimensional vectors.

Any help will be much appreciated
 
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\vec{V}_{1} = 2\hat{i} + 2\hat{j} + 3\hat{k} + \vec{V}_{2} - \vec{V}_{3}
Using substitution you should be able to solve for the 3 vectors.
 
Essentially, you are talking about solving three linear equations for the three unknowns,
V1, V2, and V3. odie5533's suggestion is good. It also appears that if you multiply the equation V1–V2 +V3 = 2i+2j+3k by 2 to get 2V1–2V2 +2V3 = 4i+4j+6k,and add that to the first equation, V1– 2V2-2V3 = -5i+7j+8k, you eliminate V3 from the equations. Treat it exactly like solving simultaneous.
 
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