Solve a double integral given area, xbar and ybar?

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SUMMARY

The discussion focuses on solving a double integral given the area, x-bar, and y-bar of a region with constant density. Specifically, it addresses the computation of the integral \(\int\int (7x - 4y) dA\) using the provided values: area \(A = 5\) and center of mass coordinates \((\overline{x}, \overline{y}) = (2, 3)\). The key equations discussed include \(\overline{x} = \frac{\int\int x dA}{\int\int dA}\) and \(\overline{y} = \frac{\int\int y dA}{\int\int dA}\), leading to the relationships \(\int\int x dA = \overline{x} \cdot A\) and \(\int\int y dA = \overline{y} \cdot A\).

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Homework Statement



If you know the area of a region with constant density, and you know xbar and ybar, then its possible to compute \int\int ax+by dA for any constant a and b. [Hint: write down the formulas for the center of mass of a region.

If A=5 and (xbar,ybar)=(2,3), Compute\int\int 7x-4y dA.

Homework Equations


xbar = double integral of x * density dA all over the double integral dA.

The Attempt at a Solution


I've tried using the area and the known values of xbar and ybar. but I really don't know where to get started. How can knowing xbar and ybar give us our bounds on the double integral?
 
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So
\overline{x}= \frac{\int\int xdA}{\int\int dA}
\overline{y}= \frac{\int\int ydA}{\int\int dA}

From those,
\int\int x dA= \overline{x}\int\int dA
\int\int y dA= \overline{x}\int\int dA

And, of course,
\int \int 7x- 4y dA= 7\int\int x dA- 4\int\int y dA
 

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