MHB Solve Algebra Question Easily: 34

  • Thread starter Thread starter Ilikebugs
  • Start date Start date
  • Tags Tags
    Algebra
Click For Summary
The discussion focuses on finding a simpler method to solve an algebra problem that results in the number 34, rather than relying on the guess and check method. Participants express enthusiasm for the problem and share solutions, with one user offering their approach in spoiler tags for others to view. The conversation highlights the desire for more efficient problem-solving techniques in algebra. Overall, the thread emphasizes collaborative problem-solving and the sharing of strategies among users.
Ilikebugs
Messages
94
Reaction score
0
View attachment 6159I know that I can use guess and check, but I was wondering if there was an easier way? I got 34
 

Attachments

  • POTW 8.png
    POTW 8.png
    11 KB · Views: 98
Mathematics news on Phys.org
Ilikebugs said:
I know that I can use guess and check, but I was wondering if there was an easier way? I got 34

Hey Ilikebugs! Nice problem! ;)

I'll put my solution in spoiler tags for other people who may like the problem as well.
First the observation: $P\ne 0$ and $Q \ne 0$, because otherwise we divide by zero.
Note that we can always multiply or divide both sides by a non-zero value, but if the value can be zero, we have to check.

Then it follows that:

[math]
\frac PQ - \frac QP = \frac{P+Q}{PQ}
\quad\Rightarrow\quad \frac{P^2-Q^2}{PQ} = \frac{P+Q}{PQ}
\quad\Rightarrow\quad (P+Q)(P-Q)=P+Q \\
\quad\Rightarrow\quad P+Q=0 \quad\textit{ or }\quad P-Q=1
\quad\Rightarrow\quad Q=-P \quad\textit{ or }\quad Q=P-1
[/math]

Considering that neither P nor Q can be zero, the first condition gives us 18 solutions, and the second 16 solutions, for a total of 34.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

Similar threads