Solve Change of Variable: Triangular to Square/Rectangle

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Homework Help Overview

The discussion revolves around the change of variable technique applied to a triangular area defined by specific vertices, with the goal of transforming it into a square or rectangular region using new variables u and v.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the feasibility of transforming a triangular region into a quadrilateral through variable substitution. There are attempts to define new variables and discuss their implications on the triangle's sides. Questions arise regarding the validity of the approach and the interpretation of certain terms like "intervals."

Discussion Status

The discussion is ongoing, with some participants questioning the original poster's method and assumptions. There is a lack of consensus on the effectiveness of the proposed change of variable, and further clarification is sought regarding the context of the problem.

Contextual Notes

Participants note that the transformation of a three-sided region into a four-sided region may not be possible, raising questions about the assumptions underlying the original problem setup.

Suitengu
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[SOLVED] Change of Variable

In case of the triangular area with vertices: (-1 1) (0 0) and (1 1), how would you do a change of variable to make that look like a square or rectangular region in terms of u an v?

x = (1/2)(u+v) y = (1/2)(u-v)

so

u = x+y v = x-y
 
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No (continuous) change of variable will make a 3 sided region into a 4 sided region!
 
oh. well what i did was to do the change of variable and then do the intervals as if i had a whole quadrilateral region and then i halved the answer. It seems to be right but i am not sure however.
 
Choosing u= x+y, v= x- y as coordinates will make two sides of the triangle, y= -x and y= x correspond to u= 0 and v= 0 respectively. The third side of the triangle, y= 1, becomes u+ v= 2.

I have no idea what you mean by "intervals" or what answer you "halved". Apparently this was part of a larger problem you haven't mentioned.
 

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