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Homework Statement
I need to work on a differential equation.
[tex] \frac{d^2T}{dx^2} - (m+n\ sin(kx))\ T = 0[/tex]
Homework Equations
Is my work correct?
The Attempt at a Solution
[tex] \frac{d^2T}{dx^2} - (m+n\ sin(kx))\ T = 0[/tex]
[tex] \frac{d}{dx}\left(\frac{dT}{dx} \right) = (m+n\ sin(kx))\ T [/tex]
[tex] \int \frac{d}{T}\left(\frac{dT}{dx} \right) = \int (m+n\ sin(kx)) \ dx[/tex]
[tex] \frac{1}{T}\left(\frac{dT}{dx} \right) = mx-\frac{n}{k}\ cos(kx)+C_1[/tex]
[tex] \int \frac{dT}{T} = \int (mx-\frac{n}{k}\ cos(kx)+C_1)\ dx[/tex]
[tex] ln T = \frac{m}{2}x^2-\frac{n}{k^2}sin(kx)+C_1x+C_2[/tex]
[tex] T = e^{\frac{m}{2}x^2-\frac{n}{k^2}sin(kx)+C_1x}\ e^{C_2}[/tex]
[tex] T = e^{\frac{m}{2}x^2-\frac{n}{k^2}sin(kx)+C_1x}\ C_2[/tex]