Solve Energy & Momentum Problem: Urgent Homework

AI Thread Summary
The discussion centers on a physics problem involving two blocks attached to a spring and the effects of a clay ball impacting one of the blocks. The conservation of momentum equation is established, indicating that the momentum before the collision equals the momentum after. Additionally, the conservation of energy principle is highlighted, emphasizing that potential energy in the spring must be considered until it returns to its equilibrium position. The conversation raises questions about the velocity of the larger block after the clay-laden block passes the equilibrium point. Understanding these principles is crucial for solving the problem effectively.
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Homework Statement



A 2kg block and an 8kg block are both attached to an ideal spring for which k=200 N/m and both are initially at rest on a horizontal frictionless surface. In an initial experiment a 0.1kg ball of clay is thrown at the 2kg block. The clay is moving horizontally with speed v when it hits and sticks to the block. The 8kg block is held still by a removable stop. As a result, the spring compresses a maximum distance of 0.4m.

In a second experiment, an identical ball of clay is thrown at another identical 2kg block, but this time the stop is removed so that the 8kg block is free to move.

e. State the principle(s) that can be used to calculate the velocity of the 8kg block at the instant that the spring regains its original length. Write the appropriate equation(s) and show the numerical substitutions, but do not solve for velocity.


Homework Equations



Pi=Pf
Ei=Ef

The Attempt at a Solution



So I use conservation of momentum and get

mclay*vclay + mblocks * 0 = ( mclay+mblocks)* vf

However, the rubric said I need to include also conservation of energy so how will it fit in here ??
 
Physics news on Phys.org
Until the first weight returns to normal relaxed spring detent, the spring contains PE. Only as it crosses the equilibrium point is it not to be accounted for.

What happens to the speed of the larger block after the clay laden block crosses that point going backward?
 
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