Solve Enjoyable Enigmas with Mr.E's Challenge

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The forum thread invites puzzle enthusiasts to share various types of puzzles, including cryptograms and whodunnits, while emphasizing that participants should know the answers without resorting to online searches. A code message is presented, which participants attempt to decode, leading to discussions about its meaning and possible interpretations. Participants also engage in solving additional puzzles, such as cutting a cake into pieces with minimal cuts and a physics challenge involving water and matchsticks. The conversation highlights the enjoyment of problem-solving and the creative thinking required to tackle these enigmas. Overall, the thread fosters a collaborative atmosphere for sharing and solving intriguing puzzles.
  • #481
consciousness said:
0.5$
This is correct, despite the fact it's unlikely you'd get this much for it at any recycling center.
 
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  • #482
Enigman said:
Don't stay inside the box or you are just like the cat...I am a curious guy, I like opening boxes... <psychopathic grin>
What did they say? Ah, yes. Curiosity killed the cat...

Go away Schrodinger! Someone might observe YOU!
 
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  • #483
zoobyshoe said:
This is correct, despite the fact it's unlikely you'd get this much for it at any recycling center.

What recycling center? *follows the examples of others around him and throws a bottle out the window*
 
  • #484
consciousness said:
Go away Schrodinger! Someone might be observe YOU!

I am the ENIGMAN. I am unobservable. My mask indiscernible. My mystery (Mr.E) unsolvable. I am outside the box. I will do the observing...
 
  • #485
Enigman said:
I am the ENIGMAN. I am unobservable. My mask indiscernible. My mystery (Mr.E) unsolvable. I am outside the box. I will do the observing...

So you cannot be observed? *Uses Occam's razor to cut Enigman out of reality!*
 
  • #486
Enigman said:
I am the ENIGMAN. I am unobservable. My mask indiscernible. My mystery (Mr.E) unsolvable. I am outside the box. I will do the observing...
I'm sorry to inform you you have been the victim of a misspelling all this time. You are actually the Eggman. No one's had the heart to tell you.
 
  • #487
consciousness said:
2$ is the total profit

I insist my answer is correct! :-p
Well, I insist that it IS correct, and I'll keep on insisting it till you're blue in the face!
 
  • #488
zoobyshoe said:
Well, I insist that it IS correct, and I'll keep on insisting it till you're blue in the face!

So you pute his answer? Well, so do I!
 
  • #489
"The instructive thing about this puzzle is that although it can easily be solved using elementary algebra, it can also be solved without any algebra at all-just by plain common sense. Moreover, the common sense solution is, in my judgement, for more interesting and informative - and certainly more creative - than the algebraic solution.

Fifty-six biscuits are to be fed to ten pets; each pet is either a cat or a dog. Each dog is to get six biscuits, and each cat is to get five. How many dogs and how many cats are there?

Any reader familiar with algebra can get this immediately. Also, the problem can be solved by trial and error: there are eleven possibilities for the number of cats (anywhere from zero to ten), so each possibility can be tried until the correct answer is found. But if you look at this problem in just the right light, there is a surprisingly simple solution that involves neither algebra nor trial and error."

What is this interesting and creative "common sense" answer?
 
  • #490
zoobyshoe said:
I'm sorry to inform you you have been the victim of a misspelling all this time. You are actually the Eggman. No one's had the heart to tell you.

Hushhh...that can't be known. I can neither confirm or deny that. If I tell you I will have to kill you...
EDIT: Possible News headline in the recent future:
the last zoobie killed by an eggman who Mr.E-ously disappears.
 
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  • #491
Enigman said:
sleep muddled, brain addled,
funny little Enigman
:blushing:
(was I hallucinating or did collinsmark too reply to this one?)

Yes, I replied with the correct
3 Shillings and 3 pennies
answer. But then I saw that you had already provided the correct answer (I had missed it at first glance) so I deleted my post.
 
  • #492
zoobyshoe said:
Fifty-six biscuits are to be fed to ten pets; each pet is either a cat or a dog. Each dog is to get six biscuits, and each cat is to get five. How many dogs and how many cats are there?
What is this interesting and creative "common sense" answer?
The sum should be 56.
units place should be 6
A-units place of biscuits eaten by cats should 0 or 5
You can get 6 in units place by (adding 1 to A=5) or (adding 6 to A=0)
B- units place of biscuits eaten by dogs can't be 1
A=0 B=6
Multiple of 6 with units place 6--> 36,6
36 satisfies all conditions
6-->dogs 4-->cats
 
  • #493
collinsmark said:
Yes, I replied with the correct
3 Shillings and 3 pennies
answer. But then I saw that you had already provided the correct answer (I had missed it at first glance) so I deleted my post.

Don't do that... I have a paranoia of having paranoid schizophrenia...
:biggrin:
 
  • #494
collinsmark said:
Yes, I replied with the correct
3 Shillings and 3 pennies
answer. But then I saw that you had already provided the correct answer (I had missed it at first glance) so I deleted my post.
Your correct answer was much better than his correct answer. He seemed to have lost the ability to form plurals: "3 Shilling, 3 Penny."
 
  • #495
Enigman said:
The sum should be 56.
units place should be 6
A-units place of biscuits eaten by cats should 0 or 5
You can get 6 in units place by (adding 1 to A=5) or (adding 6 to A=0)
B- units place of biscuits eaten by dogs can't be 1
A=0 B=6
Multiple of 6 with units place 6--> 36,6
36 satisfies all conditions
6-->dogs 4-->cats
Absolutely not!

We're looking for an "interesting, creative, 'common-sense'" answer.
 
  • #496
Those are vague guidelines, I steered clear of the more set in ground ones- No algebra; No trial and error.

Common sense is the collection of prejudices acquired by age eighteen.
-A.E.
 
  • #497
When you read the answer, you'll go "Doh!"
 
  • #498
This is still math but maybe less enough that it counts:
If there were 10 dogs, we would need 60 biscuits. We need 4 fewer biscuits so there must be 4 cats.
 
  • #499
Maximum case 60 biscuits
Actual case 56 biscuits
Shortage 4
No. of cats 4
No. of dogs 6
O_S replied already...
won't delete it.
 
  • #500
Doh!

A man marries a woman, but is not her husband. How?
 
  • #501
The clergyman?
 
  • #502
Correct. There is another answer also...

Edit-Actually the second answer may not be found by people of all cultures.
 
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  • #503
"It" is ambiguous, and could be referring to the woman, in which case it is clear that she is not her own husband
 
  • #504
Office_Shredder said:
"It" is ambiguous, and could be referring to the woman, in which case it is clear that she is not her own husband

:confused: You can read it as-

A man marries a woman, but he is not her husband. How?
 
  • #505
Hmm... somehow the first time when I read it I thought it said
"A man marries a woman, but IT is not her husband. How?"

Never mind, carry on.
 
  • #506
he is her widower? her ex-husband?
 
  • #507
Office_Shredder said:
This is still math but maybe less enough that it counts:
If there were 10 dogs, we would need 60 biscuits. We need 4 fewer biscuits so there must be 4 cats.
Right idea. The solution in the book is to make note of the fact each animal gets at least 5 biscuits. Removing 5 x 10 from the total leaves 6, which must also be the total number of dogs.
 
  • #508
@Enigman, I haven't heard this phrase used in that sense. But I have in another sense though. Not sure about you guys.
 
  • #509
Okkkaaaay...
Baseball?
 
  • #510
The Puzzleland Toy Store charges $6 for a doll, $7.50 for a train, $4.50 for a top, and $12 for a paint set.

What would you pay there for a bicycle?
 

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