Solve Equation C for F: Simple Algebra

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To solve the equation C = ABF^E - AgF^(E+1) for F, it can be rearranged into the form F^(E+1) - (B/g)F^E + C/(Ag) = 0. If E is a non-negative integer, the equation is of degree E+1, yielding E+1 possible solutions. Conversely, if E is a negative integer, the equation transforms into one involving 1/F and has -E solutions. Generally, this equation cannot be solved in closed form, but numerical methods like iterations or Newton's method can be employed to find roots. The discussion emphasizes the complexity of solving for F based on the value of E.
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How do I go about solving the following equation in terms of F?

C=ABF^E-AgF^{E+1}, where C, A, B, E represent other equations not dependent on F
 
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C=ABF^E - AgF^(E+1)
F^(E+1) - (B/g)F^E + C/(Ag) = 0

If E is a non-negative integer, then this is an algebraic equation of degree E+1 and in general has E+1 solutions.
If E is a negative integer, then this is basically an algebraic equation in 1/F and of degree -E with -E solutions.
In general this equation is not solvable in closed form but you can probably obtain a root using iterations or methods such as Newton's.
 
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