Solve F(x,y) = 0 for y = 1: Solve Equation

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To solve the equation F(x,y) = 0 for y = 1, the function simplifies to 0 = (x^2 + 1)(x + 1)(x - 1)(x + 2). The solutions found are S = {-2, -1, 1}, which are correct for real values. It is also noted that imaginary solutions may need to be considered based on the course requirements. The discussion confirms that solving directly with y = 1 is an acceptable approach.
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Homework Statement


Hello,

This factorized function F(x,y) = (x^2+y^2)(x+y)(x-y)(x+2y)

The question I need to answer is solve F(x,y) = 0 for y = 1

0 = (x^2+1^2)(x+1)(x-1)(x+2(1))

would it be this? or first I do f(x,y) = 0 then do it again with y = 1?

Homework Equations


0 = (x^2+1^2)(x+1)(x-1)(x+2(1))

The Attempt at a Solution

 
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Max0007 said:

Homework Statement


Hello,

This factorized function F(x,y) = (x^2+y^2)(x+y)(x-y)(x+2y)

The question I need to answer is solve F(x,y) = 0 for y = 1

0 = (x^2+1^2)(x+1)(x-1)(x+2(1))

would it be this? or first I do f(x,y) = 0 then do it again with y = 1?

Homework Equations


0 = (x^2+1^2)(x+1)(x-1)(x+2(1))

The Attempt at a Solution


It's just fine to solve that equation with y=1. Can you solve it?
 
Dick said:
It's just fine to solve that equation with y=1. Can you solve it?
This is what I go S = {-2,-1,1}

is this correct?
 
Max0007 said:
This is what I go S = {-2,-1,1}

is this correct?

Looks fine to me.
 
You might also have to include the imaginary answers. Depending on your class/instructor
 
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