Solve for F: \displaystyle{F = \frac{9}{5}(20) + 32}F = 68 degrees Fahrenheit

[Holocene]

Homework Statement

The relationship between degrees Fahrenheit and degree Celsius is given by the formula:

\displaystyle{C = \frac{5}{9}(F - 32)}

For what temperature will degrees Celsius be 20 more than degrees farenheit?

The Attempt at a Solution

Is this the equation to solve?

\displaystyle{\frac{5}{9}(F - 32) = F + 20}

 

[Feldoh]

Yes it is

 

[colby2152]

Homework Statement

The relationship between degrees Fahrenheit and degree Celsius is given by the formula:

\displaystyle{C = \frac{5}{9}(F - 32)}

For what temperature will degrees Celsius be 20 more than degrees farenheit?

The Attempt at a Solution

Is this the equation to solve?

\displaystyle{\frac{5}{9}(F - 32) = F + 20}

Celsius must be 20 degrees more than Farenheit, so C = F + 20 is the correct substitution.

 

[Integral]

Celsius must be 20 degrees more than Farenheit, so C = F + 20 is the correct substitution.

This is just wrong. at -40 the 2 scales are equal.

 

[HallsofIvy]

Celsius must be 20 degrees more than Farenheit, so C = F + 20 is the correct substitution.

This is just wrong. at -40 the 2 scales are equal.

What does that have to do with the question? No one is saying that "C= F+ 20" is generally true, just that it is true when "the degrees Celcius is 20 degrees more than Farenheit". C= F+ 20 is just a restatement of that.