MHB Solve for q: Q=p-q/2 q=p-2Q

  • Thread starter Thread starter OMGMathPLS
  • Start date Start date
AI Thread Summary
The discussion revolves around solving the equations Q = p - q/2 and q = p - 2Q. Participants clarify that both expressions, p - 2Q and -2Q + p, represent the same value due to the commutative property of addition. The process of isolating q involves manipulating the equations through multiplication and addition to achieve the desired form. The rationale for adding q - 2Q to simplify the left side to just q is emphasized as a key step in solving the equation. Overall, the conversation highlights the flexibility in expressing equivalent mathematical solutions.
OMGMathPLS
Messages
64
Reaction score
0
Solve for q:

Q=p-q/2

Correct answer :
p-2Q
or
-2Q+pHow can this answer be either p-2Q OR -2Q+p. I mean I can see they are the same value but how would you do it to get different answers?
 
Mathematics news on Phys.org
I assume you mean:

Q=(p-q)/2

or:

$$Q=\frac{p-q}{2}$$

Multiply through by $2$:

$$2Q=p-q$$

Add $q-2Q$ to both sides:

$$q=p-2Q$$

Now, let's go back to:

$$Q=\frac{p-q}{2}$$

Multiply through by $-2$:

$$-2Q=q-p$$

Add $p$ to both sides:

$$-2Q+p=q$$

The form you get (assuming you use valid operations), and/or choose to use depends largely on you. The commutative law of addition results in:

$$p-2Q=-2Q+p$$

Personally, I avoid the use of leading negatives whenever possible. :D
 
Thanks.Why did you add q-2Q to both sides?
 
OMGMathPLS said:
Thanks.Why did you add q-2Q to both sides?

Doing so resulted in the left side of the equation having just $q$ in it, which is what we want, as we are solving for $q$.. :D
 
Q=(p-q)/2
multiply both sides by 2 and the 2 on the right hand side cancels out

2Q=p-q
2Q-p=-q

you don't want to have -q so instead you want to end up with something for q. just flip the signs or multiply the whole thing by -.

-(2Q-p=-q)
-2Q+p=q

p-2Q is the same as p+(-2Q) and that's equivalent to -2Q+p in which both cases the the 2Q has a negative sign and the p has a positive.

hope that help! :o
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Back
Top