Solve for q: Q=p-q/2 q=p-2Q

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Discussion Overview

The discussion revolves around solving the equations Q = p - q/2 and q = p - 2Q for the variable q. Participants explore different algebraic manipulations and interpretations of the equations, focusing on the equivalence of the derived forms.

Discussion Character

  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant questions why the solutions for q can be expressed as both p - 2Q and -2Q + p, noting they are equivalent but seeking clarity on the derivation process.
  • Another participant clarifies the manipulation of the equation Q = (p - q)/2, demonstrating the steps to isolate q and showing that both forms of the solution arise from valid algebraic operations.
  • There is a discussion about the preference for avoiding leading negatives in expressions, with one participant expressing a personal preference for clarity in presentation.
  • Multiple participants emphasize the importance of manipulating equations correctly to isolate q, with one explaining that adding q - 2Q to both sides simplifies the left side to just q.
  • Another participant reiterates the equivalence of the two forms of the solution, explaining that p - 2Q can be viewed as p + (-2Q), which is the same as -2Q + p.

Areas of Agreement / Disagreement

Participants generally agree on the algebraic manipulations leading to the solutions for q, but there is no consensus on the preferred form of the expression or the clarity of the steps involved.

Contextual Notes

Some participants express confusion regarding specific steps in the algebraic manipulation, indicating potential gaps in understanding the reasoning behind certain operations.

OMGMathPLS
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Solve for q:

Q=p-q/2

Correct answer :
p-2Q
or
-2Q+pHow can this answer be either p-2Q OR -2Q+p. I mean I can see they are the same value but how would you do it to get different answers?
 
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I assume you mean:

Q=(p-q)/2

or:

$$Q=\frac{p-q}{2}$$

Multiply through by $2$:

$$2Q=p-q$$

Add $q-2Q$ to both sides:

$$q=p-2Q$$

Now, let's go back to:

$$Q=\frac{p-q}{2}$$

Multiply through by $-2$:

$$-2Q=q-p$$

Add $p$ to both sides:

$$-2Q+p=q$$

The form you get (assuming you use valid operations), and/or choose to use depends largely on you. The commutative law of addition results in:

$$p-2Q=-2Q+p$$

Personally, I avoid the use of leading negatives whenever possible. :D
 
Thanks.Why did you add q-2Q to both sides?
 
OMGMathPLS said:
Thanks.Why did you add q-2Q to both sides?

Doing so resulted in the left side of the equation having just $q$ in it, which is what we want, as we are solving for $q$.. :D
 
Q=(p-q)/2
multiply both sides by 2 and the 2 on the right hand side cancels out

2Q=p-q
2Q-p=-q

you don't want to have -q so instead you want to end up with something for q. just flip the signs or multiply the whole thing by -.

-(2Q-p=-q)
-2Q+p=q

p-2Q is the same as p+(-2Q) and that's equivalent to -2Q+p in which both cases the the 2Q has a negative sign and the p has a positive.

hope that help! :o
 

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