georg gill
- 151
- 6
\frac{ds}{dt}=600-\frac{2s}{200+t}
\frac{ds}{dt}+\frac{2s}{200+t}=600
\frac{ds}{dt}e^{ln(100+t/2)}+\frac{2s}{200+t}e^{ln(100+t/2)}=e^{ln(100+t/2)}600
\frac{d}{dt}(se^{ln(100+t/2)})=(100+t/2)600
se^{ln(100+t/2)}=\int(100+t/2)600dt
s(100+t/2)=600(100t+t^2/4)+C
t=0 s=20 000
20.000\cdot100=C
But this is wrong
I guess i want to know what I did wrong. I used the product rule for derivation backwards. Here is answer sheet
http://bildr.no/view/1051423
\frac{ds}{dt}+\frac{2s}{200+t}=600
\frac{ds}{dt}e^{ln(100+t/2)}+\frac{2s}{200+t}e^{ln(100+t/2)}=e^{ln(100+t/2)}600
\frac{d}{dt}(se^{ln(100+t/2)})=(100+t/2)600
se^{ln(100+t/2)}=\int(100+t/2)600dt
s(100+t/2)=600(100t+t^2/4)+C
t=0 s=20 000
20.000\cdot100=C
But this is wrong
I guess i want to know what I did wrong. I used the product rule for derivation backwards. Here is answer sheet
http://bildr.no/view/1051423