How to Find the Solution to 3^x = x^2?

  • Thread starter Benn
  • Start date
In summary, the conversation discusses finding all possible values of x in the equation x^2 = 3x and explores different methods of solving it, including using the Lambert W function or a fixed point iteration. It is noted that the solution is negative and can be found by taking the square root of both sides.
  • #1
Benn
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Homework Statement



Find all possible values of x:

x2 = 3x

Homework Equations





The Attempt at a Solution



I took the log of both sides.. didn't get anywhere. I'm not sure where to start.
 
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  • #2
You can't solve this analytically with logarithms. You can either guess the right answer and prove that it works, use the Lambert W function or you can use a numerical method.
 
  • #3
okays... thanks a lot!
 
  • #4
Your equation has a solution, because both functions are monotone and increasing.

[tex] 3^{-1}<(-1)^2 [/tex]

[tex] 3^0 > 0^2 [/tex]
 
  • #5
One simple way to find that solution is via a fixed point iteration. Taking the square root of both sides and recognizing that the solution is negative yields
[tex]x=-\sqrt{3^x}[/tex]
This converges to the solution fairly quickly. Quickly by fixed point iteration standards, that is. Fixed point iteration is rarely fast.
 

What is the equation "Solve for x (3^x = x^2)" asking for?

The equation is asking for the value of x that satisfies the equation 3^x = x^2.

What type of equation is "Solve for x (3^x = x^2)"?

This is an exponential equation, as it contains a variable in the exponent.

Can the equation "Solve for x (3^x = x^2)" be solved algebraically?

Yes, it can be solved algebraically by using logarithms to isolate the variable x.

What is the general method for solving an equation like "Solve for x (3^x = x^2)"?

The general method is to take the logarithm of both sides of the equation, then use logarithm properties to simplify and isolate the variable x.

Are there any restrictions or limitations when solving "Solve for x (3^x = x^2)"?

Yes, when using logarithms to solve this equation, we must make sure that the base of the logarithm is positive and not equal to 1, and the argument of the logarithm is positive.

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