Solve for X: ln(x) + ln(x+1) = 1

  • Thread starter r_swayze
  • Start date
  • #1
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Im having trouble finding the solution to this problem, can any one walk me through this?

So far I have:

ln(x) + ln(x+1) = 1

ln(x)(x+1) = 1

e^1 = x(x+1)

e^1 = x^2 + x

This is where I get stuck.
Am I on the right track?
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
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e^1 = x^2 + x

Yes this is correct. Write e^1 as just e, which is constant.
If you move it to the other side you'll get:
x2+x-e =0

Now how do you solve the equation ax2+bx+c=0?
 
  • #3
66
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Yes this is correct. Write e^1 as just e, which is constant.
If you move it to the other side you'll get:
x2+x-e =0

Now how do you solve the equation ax2+bx+c=0?

I dont think x^2 + x - e = 0 can factor out, at least not without using the quadratic formula
 
  • #4
rock.freak667
Homework Helper
6,223
31
I dont think x^2 + x - e = 0 can factor out, at least not without using the quadratic formula

Then use the wquadratic equation formula and you'd solve for x.
 

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