Solve for X: ln(x) + ln(x+1) = 1

[r_swayze]

Im having trouble finding the solution to this problem, can anyone walk me through this?

So far I have:

ln(x) + ln(x+1) = 1

ln(x)(x+1) = 1

e^1 = x(x+1)

e^1 = x^2 + x

This is where I get stuck.
Am I on the right track?

 

[rock.freak667]

e^1 = x^2 + x

Yes this is correct. Write e^1 as just e, which is constant.
If you move it to the other side you'll get:
x²+x-e =0

Now how do you solve the equation ax²+bx+c=0?

 

[r_swayze]

Yes this is correct. Write e^1 as just e, which is constant.
If you move it to the other side you'll get:
x²+x-e =0

Now how do you solve the equation ax²+bx+c=0?

I don't think x^2 + x - e = 0 can factor out, at least not without using the quadratic formula

 

[rock.freak667]

I don't think x^2 + x - e = 0 can factor out, at least not without using the quadratic formula

Then use the wquadratic equation formula and you'd solve for x.