Solve Force & Buoyancy: 1000N to Lift Concrete Block Out of Water

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To determine the force required to lift a concrete block out of water, the buoyant force and the applied force must be considered. A force of 1000N is needed to raise the block to the surface, indicating that the buoyant force is acting against the weight of the block. The density of concrete is given as 2320 kg/m³, which can be used to calculate the weight of the block in air. The force needed to lift the block in air equals the sum of the buoyant force and the 1000N applied force. Understanding these forces is essential for solving the problem effectively.
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Can anyone help me out. I don't know of any equation that i can us eto solve this A force 1000N is required to raise a concrete block to the surface of a fresh wate rlake. what is the force required to lift it out of the lake. I know that i need to figure out what the weight outside of wate ris, but i don't know how. no i don't know the volume the 1000N is the only info given. density is 2320 kg/m3.
 
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If you draw a free body diagram of the block under water you should have three forces acting on it: The block's weight, the buoyancy force and the 1000N applied force. This should tell you that the force required to lift the block in air will equal the buoyant force + 1000N.

Do you know the volume of the block?
 
srfrgrl727 said:
no i don't know the volume the 1000N is the only info given.
But are you given the density of concrete?
 
The Force you need to raise the block with the volume V to the surface is
F_1=gV(\rho_{concrete}-\rho_{water})
the force to raise the block futher is

F_2=gV\rho_{concrete}

Then \frac{F_2}{F_1}=
 
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