Solve Free Fall: Time Calculation for Rock Dropped from Tower

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To solve the problem of a rock shot vertically from a tower, one must apply the kinematic equations for constant acceleration. The key is to understand the motion of the rock, which involves both its upward trajectory and the subsequent free fall. The time of flight can be calculated using the formula t = (v0 + sqrt((v0)^2 + 2gh))/g, which combines the initial velocity, gravitational acceleration, and height of the tower. A thorough understanding of the derivation of this equation is essential, as it provides insight into the physics of the situation. Familiarity with the relevant kinematic equations will aid in solving similar problems effectively.
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I have this excerise to do:

A boy is standing on the tower o height h. He shot with his slingshot a rock vertically up with velocity v0, gravitational acceleration equals g. After what time t the rock has fallen?

Answer is t = (v0 + sqrt((v0)^2 + 2gh))/g
but how to get to it? Computationally and logically - what is the way of thinking step by step? ;)

I would be very grateful for quick answer!
 
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Please review and understand the kinematic motion equations for constant acceleration. You can find them in the " intro physics formulay" thread at the top of the page, or do a web search. The derivation of these equations should be understood before memorizing and applying them.
 
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