Solve Homework: lim as x-1+ of 2^1/x-1=infinity

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Homework Statement


A) lim as x-1 of x^2-x+1/x+1 =1/2

B)lim as x-0 of x^2 sin(1/x)=0

C) lim as x-1+ of 2^1/x-1=infinity

Homework Equations


By delta-epsilon proofs


The Attempt at a Solution



A) I took |f(x)-l| and could not factor out an x-1

B) I know that x^2 goes to 0 and that the compositions of functions have the same limit.

C) I have no clue how to evaluate limits from the right hand side!
 
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for B, |x^2sin(1/x)| = |x^2||sin(1/x)| <= ...


what do you know about the sine function? for all u we have |sin(u)| <= ...?
 
that it is bounded by 1
 
right, so let e > 0, and choose d = sqrt(e), then if |x| < d, |x^2sin(1/x)| <= |x|^2*1 < d^2 = e, i'll let you do the rest, but that's the idea though
 
C) looks really hard, I wish I could help you.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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