Solve Implicit Functions: dy/dx of y^2+2y=x^3+3x-1

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SUMMARY

The discussion focuses on finding the derivative dy/dx of the implicit function defined by the equation y² + 2y = x³ + 3x - 1. The correct approach involves differentiating both sides without dividing by y, which leads to the expression dy/dx = 3x² + 3 + (1/y²)dy/dx. This method avoids complications associated with y being zero and adheres to the chain rule for differentiation. Participants emphasize the importance of proper differentiation techniques in implicit functions.

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Homework Statement



Find dy/dx of y^2+2y = x^3+3x-1

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The Attempt at a Solution



I devided both sides by y so i got y+2 = x^3+3x-1/y
then differentiating i got dy/dx = 3x^2 +3 / dy/dx

I don't think this is right
thanks for any help
 
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What you should have gotten was

dy/dx = 3x2 + 3 + 1/y2*dy/dx

As when you differentiate 1/y with respect to x, by the chain rule you get 1/y2*dy/dx To avoid y's in the denominator, it's probably better to start by differentiating rather than dividing both sides by y (you also put off corner cases where y=0 to be dealt with later... and procrastination is always good)
 
ty:biggrin:
 

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