Solve Influenza A Virus Problem: 1368350 Viruses

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The discussion revolves around calculating the number of influenza A viruses from a given volume of saliva. The volume of saliva is 0.044 cm³, with 10^-9 of that volume containing viral particles. The calculation attempts to convert this volume into nanometers and determine the total number of viruses that landed. There is confusion regarding the conversion process, particularly about whether to multiply the exponent by three due to the cubic nature of the volume. The correct approach involves converting cubic centimeters to cubic meters and then to cubic nanometers for accurate results.
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Homework Statement



A typical virus is a packet of protein and DNA (or RNA) and can be spherical in shape. The influenza A virus is a spherical virus that has a diameter of 85 nm. If the volume of saliva coughed onto you by your friend with the flu is 0.044 cm3 and 10−9 of that volume consists of viral particles, how many influenza viruses have just landed on you?

Homework Equations


V=4/3(pi)(r^3)


The Attempt at a Solution


Volume Influenza A = 4/3(pi)(42.5^3) = 321555 nm
4.4e^11/ 321555= 1368350 viruses landed

What did I do wrong??
 
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Why 4.4x1011?
 
Isnt that the conversion of .044 Cm^3 to nanometers?
 
That's what you intended it to be, but seems to me like you made an error in calculations.

I can be wrong, it happened before. But show how you got 1011.
 
I got it by multiplying .044*10^-9
 
You're trying to change 0.044 cm^3 to nm^3. It's more complicated than just converting 0.044cm to nm
 
Dont I have to multiply the -9 by 3 since its cubed
so It will be .044*10^-27

Correct?
 
lalahelp said:
Dont I have to multiply the -9 by 3 since its cubed
so It will be .044*10^-27

Correct?

Better, but still off. That would work for conversion of cubic meter to cubic nanometers, but you are converting cubic centimeters.

Convert cm3 to m3, then m3 to nm3, that's the safest way (and half of that you already did)
 
ok thank you!
 
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