Solve Limit Calc Problem: 3^(2x) - 1 / 3^(2x) + 1

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FrostScYthe
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Hi, I did this limit, I know what it is by intuition, I just don't know how to mathematically calculate it.

lim 3^(2x) - 1
x->-inf ---------- = -1
3^(2x) + 1
 
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use l'hopital's rule
 
What is the limit as (x -> -infty) of 3x ?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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