Solve log6(x+6) - log6(x-4) = 3 | Log Subtraction Help

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Homework Help Overview

The discussion revolves around solving the logarithmic equation log6(x+6) - log6(x-4) = 3, which involves properties of logarithms and exponentiation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the manipulation of logarithmic expressions and the transition to exponential form. There are inquiries about specific steps taken to arrive at intermediate results, as well as clarifications on the correct application of logarithmic properties.

Discussion Status

Some participants are sharing their attempts and results, while others are seeking clarification on the steps involved. There is an acknowledgment of a mistake regarding the exponent used in the calculations, indicating a productive exchange of insights.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information they can share or the methods they can use.

tommy2st
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Homework Statement



log6(x+6) - log6(x-4) = 3



2. The attempt at a solution

150/36 is what i get which i simplified to 25/6.
but the program tells me I am wrong can anyone think of how I am getting this wrong
 
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I get something close, what steps did you do to get at that answer?
 
The logarithms (of the same base) are exponents so you can do:

log6(x+6) - log6(x-4) = 3

[tex]log_6 \frac{x+6}{x-4}=3[/tex]

[tex]6^3 = \frac{x+6}{x-4}[/tex]

If you made that far, then you should find the rest of the steps.
 
lewando said:
I get something close, what steps did you do to get at that answer?

i figured it out now. i was squaring the base instead of cubing it. thanks for your help tho !
 
So what did you get?
 

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