Solve Logarithmic Equation: 9_{x} + 3_{x} = \frac{4}{3}

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Homework Help Overview

The discussion revolves around solving the logarithmic equation \(9_{x} + 3_{x} = \frac{4}{3}\), which involves exponential expressions and logarithmic properties.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore rewriting the equation in terms of a single base, suggesting substitutions such as \(3^x = y\). There are attempts to apply logarithmic properties, with some questioning the effectiveness of taking the logarithm of both sides due to the presence of a sum.

Discussion Status

Some participants have provided guidance on rewriting the equation to a quadratic form, indicating a potential path forward. However, there is no explicit consensus on the final approach, as the discussion includes various interpretations and suggestions.

Contextual Notes

Participants note the challenge of simplifying logarithmic expressions involving sums, which may affect the methods considered for solving the equation.

the_storm
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Homework Statement


9[tex]_{x}[/tex] + 3[tex]_{x}[/tex] = [tex]\frac{4}{3}[/tex]


Homework Equations



Solve the equation

The Attempt at a Solution


3[tex]_{2x}[/tex] + 3[tex]_{x}[/tex] = [tex]\frac{4}{3}[/tex]
I try to take ln for both sides ...? but how and there is a plus sign between them?
 
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Put [tex]3^x=y[/tex] and solve for y.
 
the_storm said:

Homework Statement


9[tex]_{x}[/tex] + 3[tex]_{x}[/tex] = [tex]\frac{4}{3}[/tex]


Homework Equations



Solve the equation

The Attempt at a Solution


3[tex]_{2x}[/tex] + 3[tex]_{x}[/tex] = [tex]\frac{4}{3}[/tex]
I try to take ln for both sides ...? but how and there is a plus sign between them?

Taking the log of both sides won't do you any good since there's no way to simplify the log of a sum. You have a good start, though - just rewrite the equation as
[tex]3^{2x} + 3^{x} - \frac{4}{3} = 0[/tex]
This is quadratic in form. You can use micromass's suggestion or factor the equation as-is.
 
thank you guys done :) :)
 

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