Solve Momentum to Get Gamma in Relativity Theory

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The discussion centers on the derivation of the gamma factor in relativity theory, specifically how it relates to momentum and energy equations. The gamma factor, represented as γ, is defined as 1 over the square root of 1 minus (v^2/c^2). Participants clarify that in relativistic physics, momentum is expressed as p = γmv, rather than the classical definition of momentum as mass times velocity. The conversation also touches on the relationship between velocity and the speed of light, emphasizing the distinction in relativistic contexts. Understanding these concepts is crucial for grasping the implications of relativity in physics.
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I was reading a book on the theory of relativity yesterday and it said that by substituting the equation for momentum (p=mv) into the formula E^2=m^2c^4+p^2c^2..
i will be able to get this E=gamma mc^2..
I was just wondering where they get the "gamma" from? :confused: can anyone pls tell me how they get that? Thx
sry, not really good at this. :cry:
 
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gamme is equal to 1 over the square root of 1-((v^2)/(c^2))
 
You need to be careful with the notation.

E^{2}=m^{2}c^{4}+p^{2}c^{2}

and p=\gamma m v.

Daniel.
 
dextercioby said:
p=\gamma m v.

Isn't momentum=mass x velocity?
 
gunblaze said:
But isn't momentum=mass x velocity?

Not in relativistic physics. Its gamma * mass * velocity as v -> c
 
erm.. can we put velocity, v, and speed of light, c, together?
eg: v^{2}c^{2}=c^{4}
 
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but it sounds ridiculous rite? how can the velocity be equal to the speed of light?
 
k.. guys, i get it alr..thx thanks so much!
 
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