Solve Repulsive Central Field Integration Problem for Deflection Angle

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SUMMARY

The forum discussion focuses on solving the deflection angle of a particle in a repulsive central field defined by the potential energy function U = α/r², where α > 0. The key equation used is χ = | π - 2ϕ_0 |, with ϕ_0 expressed as an integral involving the limits from r_min to infinity. The user encounters difficulty in simplifying the integral after substituting the potential energy into the equation. A suggested approach includes using a trigonometric substitution to resolve the integral effectively.

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Pyroadept
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Homework Statement


Hi, I know this is a mechanics question, but I don't think the actual problem I have with it involves any mechanics, it's just integration techniques.

Find the deflection angle of a particle moving in the following repulsive central field:

U = α/r², α > 0




Homework Equations



Use the formula [tex]\int[/tex]1/(x√(x² - 1))dx = π/2 (π = pi)
where the integral limits are 1 (lower) and ∞ (upper)


The Attempt at a Solution


Hi everyone, here's what I've done so far:

I use the formula χ = | π - 2ϕ_0 |, where χ is the angle of deflection

and then ϕ_0 = [tex]\int[/tex] (ρ/r²√(1 - ρ²/r² - U(r)/E) dr

where the integral limits are r_min (lower) and ∞ (upper)

I am trying to turn this into the form given in the question to apply the formula.

First I factor out a 1/r from inside the square root and sub in the value for U(r):

ϕ_0 = [tex]\int[/tex] (ρ/r√(r² - (ρ² + α/E)) dr


But this is where I get stuck, as I can't see how to turn the (ρ² + α/E) into a 1. Can anyone please point me in the right direction?

Thanks in advance for any help! :)
 
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Hi Pyroadept! :smile:

(have an integral: ∫ :wink:)

Substitute r = [√(r² - (ρ² + α/E))]s :wink:

(btw, a simple trig substitution will give you that integral anyway)
 

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