MHB Solve Revenue Problem - Get Expert Help Now

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The discussion revolves around solving a revenue problem involving a duty reduction. The original revenue is expressed as R=0.06Q, and a new duty D is introduced, leading to the equation (2/3)R=D(3/2)Q. The user seeks guidance on setting up the proper equations without a given quantity Q. The derived formula for the new duty is D=(4/9)(R/Q), indicating a relationship between revenue and duty. Further assistance is requested to complete the solution process.
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Again here is another problem I am having trouble with.
View attachment 5644For this one

I let $x=$ amount reduced from the original duty
$6-x=$ new amount after reduction.
And knowing the formula for revenue $R=Q*P$ but I can't use it because there is no given quantity.

Please kindly guide me on how to set up proper equation for this one.
Thanks a lot!
 

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Initially, the revenue from the duty (in shillings) is given by:

$$R=0.06Q$$

When a new duty $D$ is imposed, we find:

$$\frac{2}{3}R=D\frac{3}{2}Q$$

Solving for $D$, we obtain:

$$D=\frac{4}{9}\cdot\frac{R}{Q}$$

Can you finish?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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