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solakis1
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Solve the following system of imequalities:
2x+3y-4>0
3x-4y+5>0
2x+3y-4>0
3x-4y+5>0
How about an algebraic solutionskeeter said:https://www.physicsforums.com/attachments/10382
solakis said:How about an algebraic solution
solakis said:my algebraic solution without using graphing is:
(22/17)<y<infinity and (4/3)y-85/51<x<infinity
or
-infinity<y<(22/17) and -(3/2)y +68/34<x<infity
Later i will show in details how i got that solution.
Sorry for the delay but i had a lot of work to do
To graph a system of inequalities, you first need to plot the boundary lines for each inequality. Then, shade the region that satisfies all of the inequalities. The solution to the system of inequalities is the shaded region.
To write a system of inequalities in standard form, you need to rearrange the equations so that the variables are on the left side and the constants are on the right side. The inequalities should also be written with the variable on the left side and the constant on the right side.
A system of inequalities involves inequalities (>, <, ≥, ≤) while a system of equations involves equations (=). In a system of inequalities, the solution is a range of values that satisfy all of the inequalities, while in a system of equations, the solution is a specific point that satisfies all of the equations.
To solve a system of inequalities algebraically, you need to isolate one variable in one of the inequalities and substitute it into the other inequality. This will result in a single inequality with one variable, which can then be solved to find the range of values for that variable. Repeat this process for the other variable to find the complete solution.
Yes, a system of inequalities can have no solution if the inequalities are contradictory or if the solution is outside of the given range of values. For example, if one inequality is x > 5 and the other is x < 3, there is no value of x that satisfies both inequalities.