Solve the 6 Litre Car Radiator Word Problem | 10% Antifreeze Solution

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To solve the radiator problem, the initial volume of water in the 6-litre radiator is 4 litres, as it is two-thirds full. The correct approach involves letting x represent the litres of 90% antifreeze solution being added, leading to a total volume of 4 + x litres. The equation to find the concentration of antifreeze becomes 0.9x / (4 + x) = 0.1. Solving this equation will yield the required amount of 90% antifreeze solution to achieve a 10% concentration in the radiator. This method ensures the calculations reflect the actual volumes involved.
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Ive got an assignment of word problems and can't seem to figure this one out:

A 6 Litre car radiator is 2 thirds full of water. How much of a 90% antifreeze solution (90% is alcohol by volume) must be added to it to make a 10% antifreeze solution in the radiator?

I came up with the equation: 0.9x=(0.1)(6)

but that didnt work so any help about what the way to set up the problem would be great.
 
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How much water is in the radiator?
 
4L of water
 
i tried to do it a new way which was :

4+0.9x=(0.1)(6)

but i got a negative number from that attempt so that can't be the answer
 
You are assuming that the total liquid volume in the radiator is 6 litres. If that were the case, that would mean that you were adding 2 litres of antifreeze solution. But then you would be adding .9(2)= 1.8 litres of pure antifreeze which would give a concentration of 1.8/6.0= 0.3 or 30%. That's too high so you must not be filling the radiator.

Let x be the number of litres of 90% solution you are adding. Then the total liquid volume in the radiator is 4+ x litres. The amount of pure anti-freeze you are adding is (as you say) .9x. The concentration of pure anti-freeze in the radiator is \frac{.9x}{4+ x}= .1. Solve that for x.
 
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