Solve the 6 Litre Car Radiator Word Problem | 10% Antifreeze Solution

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Homework Help Overview

The problem involves a car radiator that is partially filled with water and requires the addition of a 90% antifreeze solution to achieve a desired concentration of 10% antifreeze in the total mixture. The original poster is seeking assistance with setting up the problem correctly.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to set up equations based on the volumes and concentrations but encounters difficulties. Some participants question the assumptions about the total volume of liquid in the radiator and the implications of adding the antifreeze solution.

Discussion Status

Participants are exploring different interpretations of the problem, particularly regarding the total volume of liquid in the radiator and how it affects the concentration of antifreeze. Some guidance has been offered on how to correctly set up the equation based on the actual volumes involved.

Contextual Notes

There is a focus on understanding the relationship between the volumes of water and antifreeze solution, as well as the resulting concentration, which is central to solving the problem. The original poster's assumptions about the total volume and concentration are being critically examined.

DethRose
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Ive got an assignment of word problems and can't seem to figure this one out:

A 6 Litre car radiator is 2 thirds full of water. How much of a 90% antifreeze solution (90% is alcohol by volume) must be added to it to make a 10% antifreeze solution in the radiator?

I came up with the equation: 0.9x=(0.1)(6)

but that didnt work so any help about what the way to set up the problem would be great.
 
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How much water is in the radiator?
 
4L of water
 
i tried to do it a new way which was :

4+0.9x=(0.1)(6)

but i got a negative number from that attempt so that can't be the answer
 
You are assuming that the total liquid volume in the radiator is 6 litres. If that were the case, that would mean that you were adding 2 litres of antifreeze solution. But then you would be adding .9(2)= 1.8 litres of pure antifreeze which would give a concentration of 1.8/6.0= 0.3 or 30%. That's too high so you must not be filling the radiator.

Let x be the number of litres of 90% solution you are adding. Then the total liquid volume in the radiator is 4+ x litres. The amount of pure anti-freeze you are adding is (as you say) .9x. The concentration of pure anti-freeze in the radiator is \frac{.9x}{4+ x}= .1. Solve that for x.
 

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