Solve the initial value problem

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The discussion revolves around solving the initial value problem defined by the differential equation y'' + 2y' - 15y = 4δ(t-2) with initial conditions y(0) = 1 and y'(0) = -1. Participants analyze the characteristic equation, which has real roots r = -5 and r = 3, indicating that the solution will not involve sine or cosine functions. There is a suggestion to use the method of variation of parameters after solving the associated homogeneous equation. Confusion arises regarding the inverse Laplace transform, leading to clarifications about the correct approach. Ultimately, the participants identify mistakes in their calculations, particularly in the partial fractions decomposition.
jegues
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Homework Statement



Solve the following initial value problem

y^{''} + 2y^{'} - 15y = 4\delta(t-2), \quad y(0) = 1, \quad y'(0) = -1.

Homework Equations





The Attempt at a Solution



See figure attached for my attempt at the solution.

Does anyone see any problems? Sorry if it's kinda crunched in there.
 

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The characteristic equation for this d.e. is r^2+ 2r- 15= 0 which has real roots r= -5 and r= 3. The solution cannot possibly involve "sine" or "cosine". I suspect you have a sign error.
 
HallsofIvy said:
The characteristic equation for this d.e. is r^2+ 2r- 15= 0 which has real roots r= -5 and r= 3. The solution cannot possibly involve "sine" or "cosine". I suspect you have a sign error.


Hmmm... I can't seem to spot any errors. We haven't learned anything about the characteristic equations so I can't really relate to what you're telling me.

Is this a problem that should be solved with another method instead of using laplace transforms?
 
Hi there jegues! :smile:

What is the inverse Laplace of 1 / (s + a) ?
 
I have always disliked Laplace transform- quite frankly there is NO problem that can be solve by Laplace transform that cannot be solved by some other method (and probably simpler). What I would do with this problem is to first get the two independent solutions to the associated homogeneous equation, y''+ 2y'- 15y= 0 by solving the characteristic equation r^2+ 2r- 15= 0, then using "variation of parameters" to solve the entire equation.

As Saladsamurai suggests, you appear to be confusing the inverse Laplace transform of 1/(s+ a) with that of 1/(s^2+ a^2).
 
HallsofIvy said:
I have always disliked Laplace transform- quite frankly there is NO problem that can be solve by Laplace transform that cannot be solved by some other method (and probably simpler). What I would do with this problem is to first get the two independent solutions to the associated homogeneous equation, y''+ 2y'- 15y= 0 by solving the characteristic equation r^2+ 2r- 15= 0, then using "variation of parameters" to solve the entire equation.

As Saladsamurai suggests, you appear to be confusing the inverse Laplace transform of 1/(s+ a) with that of 1/(s^2+ a^2).

Whoops there's my mistake!

This clears things up now. :biggrin:

Thanks again!

EDIT: I also made a mistake in my partial fractions decomposition.
 
Last edited:
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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