Solve the initial value problem

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jegues
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Homework Statement



Solve the following initial value problem

[tex]y^{''} + 2y^{'} - 15y = 4\delta(t-2), \quad y(0) = 1, \quad y'(0) = -1.[/tex]

Homework Equations





The Attempt at a Solution



See figure attached for my attempt at the solution.

Does anyone see any problems? Sorry if it's kinda crunched in there.
 

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The characteristic equation for this d.e. is [itex]r^2+ 2r- 15= 0[/itex] which has real roots r= -5 and r= 3. The solution cannot possibly involve "sine" or "cosine". I suspect you have a sign error.
 
HallsofIvy said:
The characteristic equation for this d.e. is [itex]r^2+ 2r- 15= 0[/itex] which has real roots r= -5 and r= 3. The solution cannot possibly involve "sine" or "cosine". I suspect you have a sign error.


Hmmm... I can't seem to spot any errors. We haven't learned anything about the characteristic equations so I can't really relate to what you're telling me.

Is this a problem that should be solved with another method instead of using laplace transforms?
 
Hi there jegues! :smile:

What is the inverse Laplace of 1 / (s + a) ?
 
I have always disliked Laplace transform- quite frankly there is NO problem that can be solve by Laplace transform that cannot be solved by some other method (and probably simpler). What I would do with this problem is to first get the two independent solutions to the associated homogeneous equation, y''+ 2y'- 15y= 0 by solving the characteristic equation [itex]r^2+ 2r- 15= 0[/itex], then using "variation of parameters" to solve the entire equation.

As Saladsamurai suggests, you appear to be confusing the inverse Laplace transform of [itex]1/(s+ a)[/itex] with that of [itex]1/(s^2+ a^2)[/itex].
 
HallsofIvy said:
I have always disliked Laplace transform- quite frankly there is NO problem that can be solve by Laplace transform that cannot be solved by some other method (and probably simpler). What I would do with this problem is to first get the two independent solutions to the associated homogeneous equation, y''+ 2y'- 15y= 0 by solving the characteristic equation [itex]r^2+ 2r- 15= 0[/itex], then using "variation of parameters" to solve the entire equation.

As Saladsamurai suggests, you appear to be confusing the inverse Laplace transform of [itex]1/(s+ a)[/itex] with that of [itex]1/(s^2+ a^2)[/itex].

Whoops there's my mistake!

This clears things up now. :biggrin:

Thanks again!

EDIT: I also made a mistake in my partial fractions decomposition.
 
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