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- Homework Statement
- find the maximum size of a IVP coefficient size?

- Relevant Equations
- diff(T(x), x) = v/200*(45 - T(x)) + 0.015*(22 - T(x)) where T(0)=39

The following IVP

diff(T(x), x) = v/200*(45 - T(x)) + 0.015*(22 - T(x)) where T(0)=39

Describes the tempetatur T in celcius at the time x of a tub filled with water. A tub which is filled with hot water at rate of v l/min.

Lets say I am told that a guy takes a 40 min bath, and during those 40 min he doesn't want the water in the tub to become colder than 37 c.

How would I go about calculating the maximum size of v for that periode?

diff(T(x), x) = v/200*(45 - T(x)) + 0.015*(22 - T(x)) where T(0)=39

Describes the tempetatur T in celcius at the time x of a tub filled with water. A tub which is filled with hot water at rate of v l/min.

Lets say I am told that a guy takes a 40 min bath, and during those 40 min he doesn't want the water in the tub to become colder than 37 c.

How would I go about calculating the maximum size of v for that periode?