- #1

Rahmuss

- 222

- 0

1

1 2

1 3 2

3 1 4 2

1 4 2 5 3

1 6 4 2 5 3

3 1 2 6 4 7 5

1 8 2 5 3 7 4 6

3 1 4 2 9 7 5 8 6

_ _ _ _ _ _ _ _ _ _

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- Thread starter Rahmuss
- Start date

In summary, the conversation is discussing a pattern where each row represents the number of digits in that row. The first number in the sequence is placed in the first row, and then the next row is filled based on the previous row. This continues until the pattern is complete. The conversation also includes a step-by-step explanation of how to place the numbers in each row based on the previous row.

- #1

Rahmuss

- 222

- 0

1

1 2

1 3 2

3 1 4 2

1 4 2 5 3

1 6 4 2 5 3

3 1 2 6 4 7 5

1 8 2 5 3 7 4 6

3 1 4 2 9 7 5 8 6

_ _ _ _ _ _ _ _ _ _

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- #2

BicycleTree

- 520

- 0

What is the answer to this pattern?

- #3

Rahmuss

- 222

- 0

BicycleTree said:What is the answer to this pattern?

1

1 2

1 3 2

3 1 4 2

1 4 2 5 3

1 6 4 2 5 3

3 1 2 6 4 7 5

1 8 2 5 3 7 4 6

3 1 4 2 9 7 5 8 6

6 5 8 1 2 10 3 7 4 9

Now, for the reason why...

As you can see you have multiple rows, and each row number tells you how many digits are in each row. Each sequencial digit from 1 to r (where r is the row number) is in that row. S your pattern (with "0" as a place holder) is like this:

0

0 0

0 0 0

0 0 0 0

0 0 0 0 0

0 0 0 0 0 0

... etc...

So... place the first number in the sequence down:

1

Then, move to the next row since you're reached r.

Next row will give it all away; but see how it works...

Place 1, then 2; but to find out where "2" goes, you need to look at the row before it and start from the left and put it that many places over from the current number you are placing. Take this example.

1 3 2

3 1 4 2

Working on that bottom row you have

1 3 2

0 0 0 0

Place the 1:

1 3 2

Now look at the row above. Place the "2" 1 place over since the row above starts with a 1:

1 3 2

1

Now place the "3"... to do that, you'll notice in the row above that 3 comes after the 1, so you need to place the "3" 3 places to the right of the two (and this wraps around). So you then have:

1 3 2

Now place the "4" 2 places over from the "3":

1 3 2

3 1

Clear as mud? I told you it would be hard. Sorry about this one... a little too tough to be seen I guess. No real math, just a dumb pattern that's hard to see.

- #4

ArielGenesis

- 239

- 0

Now look at the row above. Place the "2" 1 place over since the row above starts with a 1:

1 3 2

1 2 0 0

Now place the "3"... to do that, you'll notice in the row above that 3 comes after the 1, so you need to place the "3" 3 places to the right of the two (and this wraps around). So you then have:

1 3 2

3 1 2 0

Now place the "4" 2 places over from the "3":

1 3 2

3 1 4 2

[white]

can you please re explain in englsih

The missing number in the puzzle is 9. The sequence follows a pattern where the first number is multiplied by 2, then the second number is added by 1, and this pattern repeats until the end of the sequence.

No, this specific puzzle can only be solved in the given order. Changing the order of the numbers would result in a different sequence and therefore a different solution.

No, this specific puzzle only has one solution. The numbers are specifically chosen to follow a specific pattern, resulting in only one possible solution.

The solution to this puzzle was derived by analyzing the given sequence and recognizing the pattern of multiplication and addition. By identifying this pattern, the missing number could be easily determined.

Yes, there are endless possibilities for creating similar puzzles with different patterns. By changing the operations (such as subtraction or division) and starting numbers, a new puzzle can be created with a different solution.

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