Solve the variance problem below - statistics

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The discussion revolves around solving a variance problem in statistics, with participants sharing their approaches and proofs. One user presents a formula for variance, demonstrating it through a mathematical proof that simplifies the calculation. There is a focus on clarifying the use of the mean in the equation, with acknowledgments of contributions from others in the thread. The conversation emphasizes the importance of accuracy in notation, specifically changing 'n' to 'N' for clarity. Overall, the thread highlights collaborative problem-solving in understanding variance.
chwala
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Homework Statement
see attached
Relevant Equations
variance
The question is below:

1635595952630.png


below is my own working;
1635596053833.png
the mark scheme for the question is below here;
1635596099561.png


i am seeking for any other approach that may be there...am now trying to refresh on stats...bingo!
 
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chwala said:
Homework Statement:: see attached
Relevant Equations:: variance

The question is below:

View attachment 291394

below is my own working;
View attachment 291395the mark scheme for the question is below here;
View attachment 291396

i am seeking for any other approach that may be there...am now trying to refresh on stats...bingo!
Here's a quicker way:
##\sum (x - \bar x)^2 = \sum x^2 - N \cdot \bar x^2##

Proof:
##\sum (x - \bar x)^2 = \sum(x^2 - 2x\cdot \bar x + \bar x^2) ##
##= \sum x^2 - 2\cdot \bar x \sum x + \sum \bar x^2 = \sum x^2 - 2\bar x \cdot N \cdot \bar x + N \bar x^2 = \sum x^2 - N \cdot \bar x^2##
All summations are from n = 1 to N.
In the proof above, I'm using the fact that ##\sum x = N \bar x##
 
Last edited:
Is the proof missing something...I will counter check it later...
 
I just had a look at your proof...thanks Mark...I wasn't certain on the last part of your equation involving the mean. Its now clear to me from my study (shown below). Bingo!

1635679616725.png
 
Last edited:
chwala said:
I just had a look at your proof...thanks Mark...I wasn't certain on the last part of your equation involving the mean. Its now clear to me from my study. Bingo!
Yes, that's it. I've edited my post to change 'n' to 'N', which I hope makes it clearer.
 

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