Solve Thermodynamics: 7.67 kg Lead & 764 g Water Boiling Pt

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The discussion revolves around a thermodynamics problem involving 7.67 kg of molten lead poured into 764 g of water at 53.3°C, aiming to determine how much water boils. The key equation mentioned is mc(ΔT) = m(water)c(ΔT), which relates the heat transfer between the lead and water. A participant suggests incorporating the latent heat of vaporization (m(vapor)Lv) into the equation to account for the phase change of water. The conversation also touches on the physical change occurring in the lead as it cools and solidifies. Understanding these principles is crucial for solving the problem effectively.
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Homework Statement



Suppose 7.67 kg of molten (liquid) lead at its melting point is poured into 764 g of water at 53.3o C. How much of the water boils?

Homework Equations


mc(detla T) = m(water)c(detla T).


The Attempt at a Solution


i m guessing i have to do the dollowing:
mc(detla T) = m(water)c(detla T)+m(vapor)Lv
am i on the right track..
thanks in advance
 
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describe the physical change that occurs in the lead.
 

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