- #1
jaypee
Can Someone please solve this for me
Log2x^log2x=4
Where 2 is the base of log and exponent.
Log2x^log2x=4
Where 2 is the base of log and exponent.
Originally posted by arcnets
lethe, I think your 1st step is invalid. I think the only answer is x=4.
Originally posted by arcnets
Oops!
Obviously I misinterpreted the problem. Seeing no brackets, I thought that the problem was (log2(x))^(log2(x))=4.
While lethe's solution is correct for log2(x^(log2(x)))=4.
IOW, I thought that a functional symbol (like 'log') has priority over a power. I must have been wrong.
Is there such a convention? Any comments?
Originally posted by lethe
i usually write multiplications to the left of the function, to avoid ambiguity. anything multiplied on the right goes in the functions argument. so multiplication before function.
A logarithmic equation is an equation in which the variable appears in the exponent of a logarithm.
To solve a logarithmic equation, you need to use the properties of logarithms to isolate the variable on one side of the equation and then solve for it using exponentiation.
The properties of logarithms include the product rule, quotient rule, power rule, and change of base rule.
"Log" is short for logarithm, which is a mathematical function that represents the power to which a base number must be raised to produce a given number.
The solution to Log2x^log2x=4 is x=16. This can be found by using the properties of logarithms to rewrite the equation as x^log2x=2^4 and then solving for x by taking the logarithm of both sides and simplifying the resulting exponential equation.