Solve Vector Math Problem: Prove a=b if au = bu, u≠0

[topgear]

Homework Statement

Show that is u ≠ 0 and au = bu, then a=b. Here u is a vector and a and b are real numbers

Homework Equations

The Attempt at a Solution

I don't see how this is possible. Maybe is it said If A=B and u ≠ 0 then au = bu. If a and b are different then they are just going to scale. The only way I can think of is just dividing by u on both sides but this seems to easy.

 

[Mark44]

Homework Statement

Show that is u ≠ 0 and au = bu, then a=b. Here u is a vector and a and b are real numbers

Homework Equations

The Attempt at a Solution

I don't see how this is possible. Maybe is it said If A=B and u ≠ 0 then au = bu. If a and b are different then they are just going to scale. The only way I can think of is just dividing by u on both sides but this seems to easy.

Division by vectors is not defined.

You're given that u ≠ 0 and that au = bu.
That's equivalent to au - bu = 0. Can you think of something you can do to work with the left side of this equation?

 

[topgear]

take out u then divide by it?

 

[Mark44]

take out u then divide by it?

I suppose you mean "factor u out." That's reasonable to do. What isn't reasonable or even valid, as I said before, is dividing by a vector.

 

[topgear]

Then how should I make u go away

 

[Mark44]

You can't make u go away. What equation do you get when you do the factoring?

 

[topgear]

U(a-b)=0

 

[Mark44]

I would write it as (a - b)u = 0, since I usually write scalar multiples of vectors as kv rather than vk.

So (a - b)u = 0. That can happen if u = 0 (which can't happen in this problem). How else can this happen?

 

[topgear]

So that means a-b=0 therefore a=b

 

[Mark44]

Yes.