Solve Word Problem: Becky Had 216 Stamps

  • Thread starter Thread starter Taylor_1989
  • Start date Start date
  • Tags Tags
    Word problem
AI Thread Summary
Becky initially had 216 stamps, and the problem involves her giving away 45 stamps to Ada and Cathy in a 4:1 ratio. The confusion arose in setting up the equations correctly, particularly in substituting values for Cathy’s stamps based on the relationships given. The correct approach involves substituting 0.75B for C and solving for B, leading to the realization that B - 45 equals 0.75B + 9. The error was in misinterpreting the equation setup, which was clarified through discussion, resolving the confusion.
Taylor_1989
Messages
400
Reaction score
14
I got the word problem off the internet, just for a bit of practice, and get slightly lost towards the end. It tells me becky had 216 stamps, the thing is I am not to sure how to set up the equation I will show my working below.


Ada, Becky and Cathy had some stamps. Cathy had 20%more stamps than Ada. Cathy had 75% as many stamps as Becky. Becky gave 45 stamps to Ada and Cathy in the ratio of 4:1 so that all three girls will have the same number of stamps.

a) How many stamps did Becky have at first?

1. C=A*120\% C=B*75\%

2. ratio \frac{45}{5}=9 9*4=369*1=9

3. B-45=C+9=A+36

This is the point of confusion, I am not quite sure how to solve for B. I know I should some how sub 1 into 3 to make the equation, but not to sure how? could someone point me in the right direction, to how to solve this.

I did convert the percentages to fraction: \frac{6}{5} and \frac{3}{4} but still did not help.

Would really apprecaite the guidence
 
Physics news on Phys.org
From this point, all you need to do is substitute .75B for C and solve for B, forgetting about A, though you can check to make sure you got it right by solving for all of the final stamp counts.
 
bossman27 said:
From this point, all you need to do is substitute .75B for C and solve for B, forgetting about A, though you can check to make sure you got it right by solving for all of the final stamp counts.

If I solve for B I get 207, I should be getting 216

Here is how I did it, I personally can't see where I am going wrong, but obviously I am somewhere: B-45=\frac{3}{4}B+9 \rightarrow 4(B-45)=3(B+9) \rightarrow 4B-180=3B+27 \rightarrow B=207
 
B - 45 = .75B + 9

.25B = 54 \Rightarrow B = 216

Your problem was that you solved it as though it was:

B - 45 = \frac{3}{4}(B+9)

and \frac{3}{4}(B+9) \neq \frac{3}{4} B + 9
 
Got it, thanks for that fella; been bugging me all day.
 
Back
Top