Solved Ring Theory Question: Integer Relatively Prime to n

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The discussion addresses a ring theory question regarding integers that are relatively prime to a given integer n. It confirms that if an integer a is relatively prime to n, then there exists an integer b in the coset a + nZ that is less than n and also relatively prime to n. The proof utilizes the division algorithm, stating that a can be expressed as a = qn + r, where 0 ≤ r < n, and establishes that if gcd(n, r) = d > 1, then d must divide a, leading to the conclusion that b = r.

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  • Understanding of ring theory concepts, specifically cosets
  • Familiarity with the division algorithm in number theory
  • Knowledge of greatest common divisor (gcd) and its properties
  • Basic comprehension of integers and their properties in modular arithmetic
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[SOLVED] ring theory question

Homework Statement


My book says that "if a is an integer relatively prime to n, then the coset a +nZ of nZ containing contains an integer b < n and relatively prime to n."

If 0< a < n, this is obvious. If a > n or 0 > a, I do not see why that statement is true.

Homework Equations


The Attempt at a Solution

 
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Actually, I do see why it is true. By the division algorithm, we have

a=qn+r, where 0 <= r < n

If gcd(n,r)=d>1, then d must divide a.

So, b=r.
 

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