Solving "6. [SFHS99 5.P.60.]" Physics Problem

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A user seeks help with a physics problem involving a 5.5 kg block pushed at a constant speed up a vertical wall with a force applied at a 30° angle. Key points of discussion include calculating the work done by the applied force, gravity, and the normal force, while applying Newton's laws and the definition of work. The user initially struggles with determining the correct values for forces and work, particularly regarding friction. After receiving guidance, they realize they misinterpreted the problem and clarify that the work done by gravity was the focus, leading to a successful resolution. The discussion emphasizes understanding force components and the application of physics principles.
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Hey everyone, my first post here, hope it's ok that it's a question...
I've got this physics problem that is absolutely stumping me, is abnormal from all the other forces problems I've done before, and uk is throwing me for a loop too...here it is:

6. [SFHS99 5.P.60.] A 5.5 kg block is pushed 3.1 m at a constant speed up a vertical wall by a constant force applied at an angle of 30.0° with the horizontal, as shown in Figure 5-23.
Figure 5-23
Assume that the coefficient of kinetic friction between the block and the wall is 0.30.

(a) Determine the work done by the force on the block
___________________ J
(b) Determine the work done by gravity on the block.
___________________ J
(c) Determine the normal force between the block and the wall.
___________________ N

Any help or hints you guys can give me would be greatly appreciated...this one has me stumped.
 
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You know there will be a normal force, find out which will it be equal to, remember the block isn't moving the x-axis so the Fx sum is zero.
Also Remember Newton's 1st Law

\sum_{i=1}^{n} \vec{F}_{i} = 0 \rightarrow \vec{v} = constant

Think in components of the applied force.
 
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Ok so I tried taking the gravitational force, 54.96N, and finding the horizontal component of that. I drew it as a triangle with 54.96N as the y leg, then did 53.96/tan 30 to find the x leg of the triangle. This gave me 93.46N, which my online homework is saying is wrong! Still confused =\
 
Applying Newton's 1st Law

\sum_{i=1}^{n} \vec{F}_{i} = 0 \rightarrow \vec{v} = constant

on x-axis

Fcos\theta - N = 0

Fcos\theta = N

On y-axis

Fsin\theta - mg - F_{f} = 0

F_{f} = \mu N

Fsin\theta - mg -\mu Fcos\theta = 0

Gravity will have a negative work because it forms 180 degrees with the displacement vector, and Fsin\theta will do the work pushing the block up.

Also remember Work definition

W = \vec{F} \cdot \vec{r}

where W is equal to

W = |\vec{F}||\vec{r}|cos\theta

where \theta is the angle between the radius vector and the force.
 
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ok I've gotten the Fapp and the Fn, now I'm just having trouble with the Ff. I used the equation Ff = uN, plugging in my normal force of 194.5 and u of .3, then multiplied that by 3.1 to get work, and entered the negative of that, but it's still telling me its incorrect. Don't understand what I'm doing wrong!
 
Didn't see your new post and edit, might be able to get it with that.
 
(a) Determine the work done by the force on the block
___________________ J
(b) Determine the work done by gravity on the block.
___________________ J
(c) Determine the normal force between the block and the wall.
___________________ N


Read the questions again, it does not ask for work done by friction... I also decided to delete my energetic solution, because it wasn't needed.
 
Whoops it was work done by gravity...easy just mgd. doh! Thanks for the help i got them all now.
 
It was a pleasure to be of help, and welcome to PF!
 
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